Answer:
Explanation:
a) The friction force must supply the necessary centripetal force.
mv²/R = μmg
v = √(μgR)
v = √(0.80(9.8)(25))
v = 14 m/s
b) The normal force of the road on the car must support the weight of the car in the vertical and provide the necessary centripetal force in the horizontal.
tanθ = (mv²/R) / (mg) = v²/Rg
tanθ = (80(1000/3600))² / (25(9.8))
tanθ = 2.0156...
θ = 63.6128...
θ = 64°
