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A reaction mixture initially contains 0.236 mol FeS and 0.670 mol HCl. Once the reaction has reached completion, what amount (in moles) of the excess reactant is left

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drpelezo

Answer:

= 0.198 mole H₂S in excess

Explanation:

A quick way to determine limiting reactant is to convert reactant values given to moles and divide by respective coefficient. The smaller value is the limiting reactant other reactants will be in excess. However, when working problem, use mole values given to solve, not results of division.

       FeS         +        2HCl          => FeCl₂ + H₂S

0.236mole/1      0.670mole/2

   = 0.236             = 0.335

limiting reactant is FeS; HCl will be in excess.

Problem solution

0.236mole FeS used + 2(0.236 mole HCl used)

=> 0.236 mole FeCl₂ + 0.236 mole H₂S + (0.670 - 0.472) mole HCl in excess or, 0.198 mole H₂S in excess.

Hope this helps.    :-)

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