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The coordinates of three vertices of a square abcd are A (-2.5,1.5) B (-2.5,-3) and C (2,1.5) When point D is placed on this square, what willl be the perimeter of the square be? PLEASE HELP ASAP

The coordinates of three vertices of a square abcd are A 2515 B 253 and C 215 When point D is placed on this square what willl be the perimeter of the square be class=

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watsonultra2

Answer:

18

Step-by-step explanation:

We know in a square ABCD, AB=CD=BC=AD

so the perimeter of ABCD will be 4AB.

now find the AB:

A(—5/2 , 3/2) so x1=—5/2 , y1=3/2

B(—5/2 , —3) so x2=—5/2 , y2= —3

AB=

[tex] \sqrt{ {(x1 - x2)}^{2} + {(y1 - y2)}^{2} } = \sqrt{ {(0)}^{2} + {4.5}^{2} } = 4.5[/tex]

Now, AB=4.5 and 4AB=18

The perimeter is 18

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