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Answer:
x = -8 or 2
Step-by-step explanation:
Compare your equation to the standard form equation.
-x^2 -6x +16 = 0 . . . . . . your equation
ax^2 +bx +c = 0 . . . . . . standard form equation
Identify the values of 'a', 'b', and 'c'.
a = -1
b = -6
c = 16
Fill in these values in the quadratic formula and do the arithmetic.
[tex]x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-(-6)\pm\sqrt{(-6)^2-4(-1)(16)}}{2(-1)}=\dfrac{6\pm\sqrt{100}}{-2}\\\\x=-3\pm5=\{-8,2\}[/tex]
The solutions are x = -8 and x = 2.
