At a carnival, food tickets cost $2 each and ride tickets cost $3 each. A total of $1,240 was collected at the carnival. The number of food tickets sold was 10 less than twice the number of ride tickets sold.

The system of equations represents x, the number of food tickets sold, and y, the number of ride tickets sold.

2x + 3y = 1240

x = 2y – 10

How many of each type of ticket were sold?

180 food tickets and 293 ride tickets
180 food tickets and 350 ride tickets
293 food tickets and 180 ride tickets
350 food tickets and 180 ride tickets

Respuesta :

Answer:

180 food tickets and 350 ride tickets

Step-by-step explanation:

The number of food tickets sold is 180 and ride tickets is 350.

In order to determine how many of each type of ticket was sold, the two equations given have to be solved simultaneously using the substitution method.

2x + 3y = 1240 equation 1

x = 2y – 10 equation 2

Substitute for x in equation 1

2(2y -10) + 3y = 1240

4y - 20 + 3y = 1240

Combine similar terms

7y = 1240 + 20

7y = 1260

Divide both sides of the equation by 7

y = 1260 / 7

y = 180

Substitute for y in equation 1

2x + 3(180) = 1240

2x + 540 = 1240

2x = 1240 - 540

2x = 700

x = 700 / 2

x = 350

To learn more about simultaneous equations, please check: https://brainly.com/question/25875552