the distance between the points (x1,y1) and (x2,y2) is
D=[tex] \sqrt{(x2-x1)^2+(y2-y1)^2} [/tex]
given
(-3,3) and (3,-3)
D=[tex] \sqrt{(3-(-3))^2+(-3-3)^2} [/tex]
D=[tex] \sqrt{(3+3)^2+(-6)^2} [/tex]
D=[tex] \sqrt{(6)^2+36} [/tex]
D=[tex] \sqrt{36+36} [/tex]
D=√72
D=(√36)(√2)
D=6√2
the disatnce is 6√2
about 8.48
answer is A
