The magnitude of the kayaker's resultant velocity is 4.96 m/s.
The direction of the kayaker’s resultant velocity from the triangle is 20⁰ South of west.
The magnitude of the kayaker's resultant velocity is calculated by drawing the vector representation of the velocity to form a triangle, with side lengths of 3.7 m/s and 4 m/s, with 80⁰ angle between the two sides.
Let the resultant velocity = R
[tex]R^2 = 3.7^2 + 4^2 - 2(3.7 \times 4)\times cos (80)\\\\R^2 = 24.55\\\\R = \sqrt{24.55} \\\\R = 4.96 \ m/s[/tex]
The direction of the kayaker’s resultant velocity from the triangle is 20⁰ South of west (alternate angles).
Learn more about resultant velocity here: https://brainly.com/question/24767211
Answer:
7.2 m/s
49 south of west
Explanation:
I got it correct on Edge. :)
