Yochanan walked from home to the bus stop at an average speed of 5 km/h he immediately got on his school bus and traveled at an average speed of 60 km/h until he got to school. the total distance from his home to school is 35 kilometers, and the entire trip took 1.5 hours. how many kilometers did yochanan cover by walking, and how many kilometers did he cover by travelling on the bus? yochanan walked kilometers and traveled kilometers on the bus.

Respuesta :

distance by bus --- x km
distance walking -- 35-x km

x/5 + (35-x)/60 = 1.5
times 60
12x + 35-x = 90
11x = 55
x = 5

he walked 5 km, and went 30 km by bus

check:
time walking = 5/5 = 1 hr
time on bus = 30/60 = 1/2 hr
total is 1.5 hrs

The total time will remain constant in any journey.

And the relation between speed and time must be known.

Thus, he walked 5 km and went 30 km by bus.

What is the linear system?

It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.

Relation between speed, distance, and time.

[tex]\rm Average\ Speed = \dfrac{Distance}{Time}[/tex]

Given

Yochanan walked from home to the bus stop at an average speed of 5 km/h he immediately got on his school bus and traveled at an average speed of 60 km/h.

The total distance from his home to school is 35 kilometers, and the entire trip took 1.5 hours.

Let, he walked x km.

And bus traveled will be (35 - x).

We know that the total time will remain constant.

Total time = Time taken for walking + Time taken for traveling by bus

[tex]\rm T = T_1+T_2[/tex]

Then

[tex]\rm 1.5 = \dfrac{x}{5} + \dfrac{35-x}{60}[/tex]

Then solve this for x.

[tex]\begin{aligned} 1.5 &= \rm {\dfrac{x}{5} + \dfrac{35-x}{60}}\\\\\rm \dfrac{12x +35 - x}{60} &= 1.5\\\\\rm 11x +35 &= 90\\\\\rm 11x &= 55\\\\\rm x = 5\\\end{aligned}[/tex]

Thus, he walked 5 km and went 30 km by bus.

More about the linear system link is given below.

https://brainly.com/question/20379472