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The work done in lifting a 600-N barbell 1.6m above the floor.
What is the gain of potential energy of the barbell when it is lifted to this height?
Express your answer to two significant figures and include the appropriate units.

Respuesta :

1) Work done = Force × Displacement
Here, F = 600 N
d = 1.6 m

Substitute their values into the expression:
W = 600 × 1.6
W = 960 Nm

2) Gain in potential energy = Uf - Ui
ΔU = 960 - 0
ΔU = 960 Joules

3) In two significant figures, it would be:
  9.6 × 10² Joules

Hope this helps!

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