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A ball with a mass of 1.5 kilograms is tied to the end of a rope. The ball is pulled to a height of 0.5 meters above the ground and released.

The ball has joules of potential energy at position B. At position A, all of the energy changes to kinetic energy. The velocity of the ball at position A is meters/second. Assume there’s no air resistance. Use g = 9.8 m/s2 , PE = m × g × h, and

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MissPhiladelphia

Solve the potential energy at point B

PE = mgh

Where m is the mass

G is the acceleration due to gravity 9.8 m/s2

H is the height

PE = ( 1.5 kg) ( 9.8 m/s2) (0.5 m)

PE = 7.35 J

 

Solve the velocity using the

KE = 0.5mv^2

Where ke is the kinetic energy

M is the mass

V is the velocity

Since all energy is converted to KE

So KE = PE

 

7.35 = 0.53(1.5) v^2

V = 3.13 m/s

Lanuel

The velocity of the ball at position A is equal to 3.13 m/s.

Given the following data:

  • Mass of ball = 1.5 kilograms.
  • Height = 0.5 meters.
  • Acceleration due to gravity = 9.8 [tex]m/s^2[/tex]

How to calculate potential energy.

Mathematically, potential energy is given by this formula:

[tex]P.E = mgh\\\\[/tex]

Where:

  • m is the mass.
  • h is the height.
  • g is acceleration due to gravity.

Substituting the given parameters into the formula, we have;

[tex]P.E = 1.5 \times 9.8 \times 0.5[/tex]

P.E = 7.35 Joules.

Assuming there’s no air resistance, the potential energy would be equal to kinetic energy.

[tex]P.E = K.E\\\\7.35 = \frac{1}{2} mv^2\\\\mv^2 = 7.35 \times 2\\\\1.5v^2 = 14.7\\\\v=\sqrt{\frac{14.7}{1.5} } \\\\v=\sqrt{9.8}[/tex]

V = 3.13 m/s.

Read more on potential energy here: https://brainly.com/question/1242059

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