Respuesta :
Let, the numbers are: x,(x+1),(x+2)
It is given that, x + x+1 + x+2 = 54
3x + 3 = 54
3x = 54 - 3
3x = 51
x = 51/3
x = 17
Also, x+1 = 17+1 = 18 & x+2 = 17+2 = 19
In short, Your Numbers would be 17, 18, 19
Hope this helps!
It is given that, x + x+1 + x+2 = 54
3x + 3 = 54
3x = 54 - 3
3x = 51
x = 51/3
x = 17
Also, x+1 = 17+1 = 18 & x+2 = 17+2 = 19
In short, Your Numbers would be 17, 18, 19
Hope this helps!
the numbers that are consecutive are 1 apart
they are
x,x+1,x+2
the sum is 54
x+x+1+x+2=54
3x+3=54
minus 3 both sides
3x=51
divide by 3 bot sides
x=17
x+1=18
x+2=19
th enumbers are 17,18,19
they are
x,x+1,x+2
the sum is 54
x+x+1+x+2=54
3x+3=54
minus 3 both sides
3x=51
divide by 3 bot sides
x=17
x+1=18
x+2=19
th enumbers are 17,18,19