Answer:
2775 ways
Step-by-step explanation:
We have been given the case to choose exactly two tails when flipped 75 times means [tex]^{75}C_2[/tex]
Since, [tex]^nC_r[/tex] is equal to [tex]\frac{n!}{r!\cdot(n-r)!}[/tex]
Here n =75, r=2 substituting the values we will get
[tex]\frac{75!}{2!(75-2)!}[/tex]
[tex]n!=n\cdot (n-1)\cdot (n-2).....1[/tex]
After simplification we will get [tex]\frac{75\cdot 74\cdot 73!}{2!\cdot73!}[/tex]
Cancel out the common term that is 73! we will get
after more simplification we will get [tex]\frac{75\cdot 74\cdot}{2!}[/tex]
Finally, we will get [tex]\frac{75\cdot 74\cdot}{2}=75\cdot37=2775[/tex]
