Answer:
The probability that the sum of the numbers rolled is either a multiple of 3 or 4 is 5/9.
Step-by-step explanation:
As given: Franklin rolls a pair of six-sided fair dice with sides numbered 1 through 6.
A pair of dice has 36 possible outcomes.
The probability that the sum of the numbers rolled is either a multiple of 3 or 4 is [tex]20/36[/tex] or [tex]5/9[/tex]
Let 'A' and 'B' be the events that the sum of the numbers rolled is a multiple of 3 and a multiple of 4 respectively.
Set for A = {(1, 2), (1, 5), (2, 1), (2, 4), (3, 3), (3, 6), (4, 2), (4, 5), (5, 1), (5, 4), (6, 3), (6, 6)}, and set for B = {(1, 3), (2, 2), (2, 6), (3, 1), (3, 5), (4, 4), (5, 3), (6, 2), (6, 6)}.
So, together they form 20 sets ((6,6) is repeating so take once)
Hence, we get 20/36=5/9
