Respuesta :
Mhm, absolutely. Notice that we do not have a common unit circle value for any division of 8. But we do have a value for is 7pi/4. Now in order to actually get the value of 7pi/8, we use a half angle formula. So what we do is we will write out the formula and plug 7pi/4 into that formula, this will give us the value of 7pi/8. So the formula we need to plug 7pi/4 into is this:
±1+cos2θ2−−−−−−−−−√SO if you plug in 7pi/4 for theta in that formula, you think you could simplify it to find 7pi/8?
cos²(7pi/8)
cos²(7π/8)
But π radians = 180°
7π/8 = 7*180/8 = 157.5°
cos²(7π/8) = cos²(157.5°) = (cos(157.5))²
cos 157.5 = - cos(180 - 157.5) Second quadrant angle
cos 157.5 = -cos22.5
cos²157.5 = cos²22.5.....................(a)
Note: cos2θ= 2cos²θ - 1 Trigonometric Identity
cos45 = 2cos²(45/2) - 1
cos45 = 2cos²22.5 - 1 cos 45 = √2/2
√2/2 = 2cos²22.5 - 1
√2/2 + 1 = 2cos²22.5
2cos²22.5 = √2/2 + 1
cos²22.5 = (√2/2 + 1)/2
Recall equation (a)
cos²157.5 = cos²22.5.....................(a)
cos²157.5 = cos²22.5 = (√2/2 + 1)/2
Therefore cos²(7pi/8) = cos²157.5 = cos²22.5 = (√2/2 + 1)/2
Hope this explains it.
cos²(7π/8)
But π radians = 180°
7π/8 = 7*180/8 = 157.5°
cos²(7π/8) = cos²(157.5°) = (cos(157.5))²
cos 157.5 = - cos(180 - 157.5) Second quadrant angle
cos 157.5 = -cos22.5
cos²157.5 = cos²22.5.....................(a)
Note: cos2θ= 2cos²θ - 1 Trigonometric Identity
cos45 = 2cos²(45/2) - 1
cos45 = 2cos²22.5 - 1 cos 45 = √2/2
√2/2 = 2cos²22.5 - 1
√2/2 + 1 = 2cos²22.5
2cos²22.5 = √2/2 + 1
cos²22.5 = (√2/2 + 1)/2
Recall equation (a)
cos²157.5 = cos²22.5.....................(a)
cos²157.5 = cos²22.5 = (√2/2 + 1)/2
Therefore cos²(7pi/8) = cos²157.5 = cos²22.5 = (√2/2 + 1)/2
Hope this explains it.