Captain Jessica has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Luis and his merciless band of thieves. The Captain has probability 4/9 of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability 1/4 ​​.If both fire their cannons at the same time, what is the probability that both the pirate and the Captain hit each other's ships?

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Answer: Probability that both the pirate and the Captain hit each other's ships is [tex]\frac{1}{9}[/tex]

Step-by-step explanation:

since we have given that

Probability that the captain hits the pirate ship is given by

[tex]\frac{4}{9}[/tex]

Probability that the pirate hits the Captains's ship is given by

[tex]\frac{1}{4}[/tex]

So, we have to find the "Probability that both the pirate and the Captain hit each other's ship"  is given by

[tex]P(\text{Captain hits})\times P(\text{ Pirates hit})\\\\=\frac{4}{9}\times \frac{1}{4}\\\\=\frac{1}{9}[/tex]

Hence, probability that both the pirate and the Captain hit each other's ships is [tex]\frac{1}{9}[/tex]

The probability that both the pirate and the Captain hit each other's ships is [tex]\dfrac{1}{9}[/tex]. This can be calculated by calculating the joint probability of both events.

What is joint probability?

A joint probability is a probability that two events will occur together and at the same time. Simply it is the probability that A occurs at the same time when B occurs. It can be calculated as:

[tex] P(A and B) = P(A) * P(B) [/tex], where P(A and B) is the joint probability of A and B occurring together, P(A) is the probability of A, and P(B) is the probability of B.

Given:

The probability of Captain hitting the pirate ship is  [tex]\dfrac{4}{9}[/tex]

The probability of pirate hitting the Captain's ship is [tex]\dfrac{1}{4}[/tex].

Therefore the joint probability will be:

[tex]\dfrac{4}{9}\times\dfrac{1}{4} = \dfrac{1}{9}[/tex]

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