[tex](2n)^2+(2n+2)^2=(2n+4)^2\\
4n^2+4n^2+8n+4=4n^2+16n+16\\
4n^2-8n-12=0\\
4(n^2-2n-3)=0\\
n^2-2n-3=0\\
n^2+n-3n-3=0\\
n(n+1)-3(n+1)=0\\
(n-3)(n+1)=0\\
n=3 \vee n=-1\\\\
\underline{n=3}\\
2n=6\\
2n+2=8\\
2n+4=10\\\\
\underline{n=-1}\\
2n=-2\\
2n+2=0\\
2n+4=2[/tex]
6,8,10 or -2,0,2
