Three terms of an arithmetic sequence are shown below. Which recursive formula defines the sequence? f(1) = 6, f(4) = 12, f(7) = 18

Respuesta :

f(n) = 2(n+2)

can also be written as
f(n) = 2n + 4

Answer:

The recursive formula defines the sequence is [tex]f(n)=f(n-1)+2[/tex].

Step-by-step explanation:

Three terms of an arithmetic sequence are

f(1) = 6

f(4) = 12

f(7) = 18

It means first term is 6, fourth term is 12 and seventh term is 18.

The formula for nth term of an arithmetic sequence is

[tex]a_n=a+(n-1)d[/tex]

where n is number of term, a is first term and d is common difference.

4th term of the AP is

[tex]a_n=6+(4-1)d[/tex]

[tex]12=6+3d[/tex]                  [tex][\because a_4=f(4)=12][/tex]

Subtract 6 from both sides.

[tex]12-6=3d[/tex]

[tex]6=3d[/tex]

Divide both sides by 3.

[tex]2=d[/tex]

The common difference is 2.

The recursive formula for an AP is

[tex]a_n=a_{n-1}+d[/tex]

Substitute d=2 in the above equation.

[tex]a_n=a_{n-1}+2[/tex]

It can be written as

[tex]f(n)=f(n-1)+2[/tex]

Therefore the recursive formula defines the sequence is [tex]f(n)=f(n-1)+2[/tex].