Respuesta :
Answer:
Neither Even nor Odd
Step-by-step explanation:
We are given that
[tex]f(x)=x^2-2x\\f(1)=1^2-2(1)\\=1-2\\=-1\\f(-1)=(-1)^2-2(-1)\\=1+2\\=3[/tex]
Hence f(-1) ≠ f(1)
And neither f(-1)=-f(1) nor f(-1)=f(1)
Hence it is neither an even function nor an odd function
Answer:
Go in this order: 2, 5, 3
So it will look like: The function is f(x) = 2 (x - 5)^2 + 3.
Hope this helps, good luck :)
