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What is the electric field experienced by a charged balloon if the charge on the balloon is 9.4 × 10-10 coulombs and the force it experiences is 8.2 × 10-2 newtons?

Respuesta :

We know, F = q.E
E = F/q
Here, F = 8.2 * 10⁻²
q = 9.4 * 10⁻¹⁰

Substitute values into the expression:
E = 8.2 * 10⁻² / 9.4 * 10⁻¹⁰
E = 8.72 * 10⁷ N/C

Hope this helps!

Answer:

Electric field, [tex]E=8.72\times 10^7\ N/C[/tex]

Explanation:

It is given that,

Charge on the balloon, [tex]q=9.4\times 10^{-10}\ C[/tex]

Force experienced by the balloon, [tex]F=8.2\times 10^{-2}\ N[/tex]

The relation between electric force and electric field is given by :

[tex]E=\dfrac{F}{q}[/tex]

[tex]E=\dfrac{8.2\times 10^{-2}}{9.4\times 10^{-10}}[/tex]

[tex]E=8.72\times 10^7\ N/C[/tex]

Hence, the electric field experienced by a charged balloon is [tex]8.72\times 10^7\ N/C[/tex]