Mr.Pham mowed 2/7 of his lawn. His son mowed 1/4 of it. Who mowed most? How much of the lawn still needs to be mowed?

Respuesta :

2/7 = 8/28
1/4 = 7/28
Therefore Mr Pham mowed more.
8+7 = 15 so 15/28 of lawn has been mowed, therefore 13/28 of the lawn is left still to be mowed.

Fractions are be used to specify the proportional relationships between

the mowing area of the lawn.

Mr. Pham mowed the most.

The fraction of the lawn that still needs to be mowed is [tex]\dfrac{13}{28}[/tex].

Reason:

The given parameters are;

The proportion of the lawn Mr. Pham mowed = 2/7 of the lawn

The proportion of the lawn mowed by his son = 1/4

Required:

The one that mowed most of the lawn, out of Mr. Pham and his son

Solution;

[tex]\dfrac{1}{4} = \dfrac{1 \times 2}{4 \times 2} = \dfrac{2}{8}[/tex]

The proportion of the lawn mowed by his son = [tex]\dfrac{1}{4}[/tex] = [tex]\dfrac{2}{8}[/tex]

Given that the denominator of [tex]\dfrac{2}{8}[/tex], is larger than [tex]\dfrac{2}{7}[/tex], and the fraction with

equal numerator and larger denominator is smaller, we have;

[tex]\dfrac{2}{8} \ is \ smaller \ than\ \dfrac{2}{7}[/tex]

Therefore;

[tex]\dfrac{2}{7} \ is \ larger \ than\ \dfrac{2}{8}[/tex]

The portion of the land mowed by Mr. Pharm is larger than the portion mowed by son.

Therefore, Mr. Pham mowed the most.

Required:

The portion of the lawn that still needs mowing.

Solution:

The remaining portion of the lawn is [tex]1 - \left(\dfrac{2}{7} + \dfrac{1}{4} \right) = \dfrac{13}{28}[/tex]

Therefore, [tex]\dfrac{13}{28}[/tex] of the lawn still needs to be mowed.

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