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A. Write the equation for the line labeled Line 1.
B. Write the equation for the line labeled Line 2.
C. Write the equation of a line that would be parallel to Line 2.
D. Write the equation of a line that would be perpendicular to Line 2.

A Write the equation for the line labeled Line 1 B Write the equation for the line labeled Line 2 C Write the equation of a line that would be parallel to Line class=

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MissPhiladelphia
Line 1 is a horizontal line so the equation of the line for line 1 is Y = 8   Line 2, first solve the slope of the line using points ( -4 , -5) and ( 0, -2)   M = (y1 – y2) / (x1 – x2) M = ( -5 – ( -2)) / ( -4 – 0) M = ¾ Since its y intercept is at ( 0,-2) B = -2 Y = ¾ x -2   For c and d you should give a point at which the line is perpendicular or parallel

a)

The line labelled l1 is a horizontal line.

The equation of the horizontal line is y = b, where b is the point where it intersects the y axis.

Line l1 intersects the y axis at (0,8).

The equation of line l1 is y = 8.

b)

Line l2 passes through (4,1) and (0,-2)

m=Slope of line = [tex]\frac{-2-1}{0-4}= \frac{-3}{-4}= \frac{3}{4}[/tex]

Also -2 is the y intercept.

So b = -2

The equation is

y=mx+b

y= [tex]\frac{3}{4}x-2[/tex]

3)

Any line parallel to the given line has the same slope but different y intercept.

So y = [tex]\frac{3}{4}x+2[/tex]

shall be the equation of a line parallel to line l2

d)

For a perpendicular line its slope is -1/m

Slope = [tex]-\frac{1}{ \frac{3}{4} }=-\frac{4}{3}[/tex]

Let the y intercept be 1

The equation of line shall be

[tex]y=- \frac{4}{3}x+1[/tex]

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