line A: y=-1/2x+3
line B:y=2x+-4

what is the slop of line A                    ps: you might need to graph it

what is the slop of line B

what is the solution to this system of equations

Respuesta :

A) For the equation [tex]y=- \frac{1}{2}x+3[/tex], the slope is [tex]- \frac{1}{2} [/tex].
Slope-intercept form is y = mx + b, where m is slope and b is the y-intercept. This means that if [tex]m=- \frac{1}{2} [/tex], the slope is  [tex]- \frac{1}{2} [/tex].

B) Since this equation is in the same form, you just find what m is equal to.
Since [tex]m=2[/tex], that's the slope.

For the solution, set [tex]y=- \frac{1}{2}x+3[/tex] equal to [tex]y=2x-4[/tex], so it would be put together like this:
[tex]y=[tex]- \frac{1}{2}x+3=2x-4\\ -\frac{1}{2}=2x-7\\ 1\frac{1}{2}x=-7\\ x=-4.66667[/tex]
So your answer is -4.667.