A 2.0x10^3kg car accelerate from rest under the actions of two forces. one is a forward force of 1140n provided by traction between the wheels and the road. the other is a 950n resistive force due to frictional forces. use the work-kinetic energy theorem to determine how far the car must travel for its speed to reach 2.0m/s.
For the answer to the question above, at the end, the KE = 1/2mv^2 = (1/2)(2000)(2^2) = 4000 J This must equal the net work acting on the car. W=Fd The net force is 1140-950= 190N. so, d=W/F = 4000/190 = 21.05 m
