The numerator factored is [tex](x+9)(x-1)[/tex] The denominator factored is [tex](x+1)(x-1)[/tex] The x coordinate for the hole comes from the like factor (x - 1). Set it equal to zero. x - 1 = 0 so x = 1 Plug the x value into the remaining fraction [tex] \frac{x+9}{x+1} [/tex] [tex] \frac{1+9}{1+1} = \frac{10}{2} =5[/tex] The answer is (1,5)
