Respuesta :
TO determine the solution set of the equations given above, we can use substitution method. We do as follows:
y = –x2 + 6x + 16 and y = –4x + 37
–x2 + 6x + 16 = –4x + 37
-x^2 +10x -21 = 0
x = 7 and 3
y = 9 and 25
Therefore, option C is the correct answer.
y = –x2 + 6x + 16 and y = –4x + 37
–x2 + 6x + 16 = –4x + 37
-x^2 +10x -21 = 0
x = 7 and 3
y = 9 and 25
Therefore, option C is the correct answer.
Answer: c.(3, 25) and (7, 9)
y = –x^2 + 6x + 16 and y = –4x + 37
Plug in -4x+37 for y in first equation . It becomes
[tex] -x^2 + 6x + 16= -4x+37 [/tex]
Combine like terms. add 4x and subtract 37 on both sides
[tex] -x^2 + 10x - 21=0 [/tex]
Divide the whole equation by -1 to remove negative sign from -x^2
[tex] x^2 - 10x + 21=0 [/tex]
Now factor the left hand side
(x-7)(x-3) = 0
x-7 =0 and x-3=0
x= 7 and x=3
Now we find out y using y = –4x + 37
when x= 7 , then y=-4(7) +37 = 9
when x= 3, then y=-4(3) + 37 = 25
We write solution set as (x,y)
(7,9) and (3,25) is our solution set