So the formula is equal to
M1v1 + I = m2v2
Where m is the mass of the object
V is the velocity of the object
I is the impulse applied
(1000 kg) (20 m/s) – 2000 = m2v2
20000 – 2000 = m2v2
18000 = m2v2
Since the car did change its mass, m1 = m2
18000 = (1000)v2
V2 = 18 m/s east
The Final velocity ( V₂ ) of the car after the impulse has been applied is ; ( A ; 18.0 m/s east
Given data :
Mass of car = 1000 kg
Initial velocity of car = 20.0 m/s east
Impulse experienced by car = 2000 N.s west
V₂ ( final velocity ) after impulse is applied = ?
To determine the final velocity Apply the formula below
M₁V₁ + Impulse = M₂V₂ ------- ( 1 ) note : M₁ = M₂
since Impulse is applied in opposite direction to the movement of the car
Equation ( 1 ) becomes
1000 ( 20 ) - 2000 = 1000 ( V₂ )
∴ V₂ = ( 20000 - 2000 ) / 1000
= ( 18,000 ) / 1000
= 18.0 m/s east
Hence we can conclude that the final velocity of the car after the Impulse is applied is 18.0 m/s east.
Learn more : https://brainly.com/question/20900398
