Respuesta :
the answer:
the relationship between elementary charge, potential difference and electrical potential energy is given by
E= qV
E: lectrical potential energy
q: elementary charge
V: potential difference
but we have e=abs val(q)=3
so we have E= qV=3ex4.5V=13.5 eV
the answer is (4)13.5 eV
the relationship between elementary charge, potential difference and electrical potential energy is given by
E= qV
E: lectrical potential energy
q: elementary charge
V: potential difference
but we have e=abs val(q)=3
so we have E= qV=3ex4.5V=13.5 eV
the answer is (4)13.5 eV
The change in electrical potential energy of the particle will be 13.5 eV. The correct option is 4.
What is electric potential?
The amount of work required to move a unit charge from a reference point to a specific point against an electric field is referred to as electric potential.
The reference point is typically Earth, but any point beyond the influence of the electric field charge can be used.
It is known that:
E = qV
Given that,
q = 3.00e
V = 4.50 V,
E = 3e x 4.5V
E = 13.5 eV.
Thus, the change in electrical potential energy of the particle will be 13.5 eV, i.e., option 4.
For more details regarding electric potential, visit:
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