Answer: We get that Camera B i.e. Second camera cover the greatest angle.
Step-by-step explanation:
Since we have given that
AB= 158 feet
BC = 121 feet
AC= 140 feet
We need to find the each angles.
First we need to find the angle A:
[tex]121=\sqrt{140^2+158^2-2\times 140\times 158\cos A}\\\\121=\sqrt{44564-44240\cos A}[/tex]
[tex]121^2=44564-44240\cos A\\\\14641-44564=-44240\cos A\\\\29923=44240\cos A\\\\\frac{29923}{44240}=\cos A\\\\0.67=\cos A\\\\\cos^{-1}(0.67)=A\\\\68.28\textdegree=A[/tex]
Similarly, we will find the angle B,
[tex]\frac{A}{\sin A}=\frac{B}{\sin B}\\\\\frac{121}{68.28}=\frac{140}{\sin B}\\\\\sin B=\frac{140\times 68.28}{121}\\\\\sin B=79\textdegree[/tex]
So, Angle C will be
[tex]\angle C=180\textdegree-(68.28\textdegree+79\textdegree)\\\\\angle C= 32.72\textdegree[/tex]
Hence, we get that Camera B i.e. Second camera cover the greatest angle.
