Answer: The required approximate volume of the given cone is 508.68 cm³.
Step-by-step explanation: We are given to find the approximate volume of the cone shown in the figure.
The VOLUME of a cone with radius of the base r units and height h units is given by
[tex]V=\dfrac{1}{3}\pi r^2h.[/tex]
For the given cone, we have
r = 9 cm and h = 6 cm.
Therefore, the VOLUME of the given cone is
[tex]V\\\\\\=\dfrac{1}{3}\pi r^2h\\\\\\=\dfrac{1}{3}\times3.14\times9^2\times6\\\\\\=3.14\times162\\\\=508.68.[/tex]
Thus, the required approximate volume of the given cone is 508.68 cm³.
