contestada

An acute angle θ is in a right triangle with cos θ = nine tenths. What is the value of sec θ?

Respuesta :

We have
[tex]\cos \theta=\frac{9}{10}[/tex]

For secant, we use
[tex]\sec \theta=\frac{1}{\cos \theta}=\frac{1}{9/10}=\frac{10}{9}[/tex]

Answer:[tex]\frac{10}{9}[/tex]

Step-by-step explanation:

Trigonometric is made up of two words trigon and metric .

Trigon means triangle and metric means measurement .

Trigonometric ratios basically define the relationship between the angles and sides .

We talk about trigonometric ratios in a right angled triangle .

For any triangle , there are six trigonometric ratios .

We have trigonometric ratios : [tex]\sin \theta \,,\,\cos \theta \,,\,\tan \theta \,,\,\csc \theta \,,\,\sec \theta \,,\,\cot \theta[/tex] such that following relations hold :

[tex]\csc \theta =\frac{1}{\sin \theta }\\\\\sec \theta =\frac{1}{\cos \theta }\\\\\cot \theta =\frac{1}{\tan \theta }[/tex]

Given: [tex]\cos \theta =\frac{9}{10}[/tex]

To find : [tex]\sec \theta[/tex]

Solution:

We know that [tex]\sec \theta =\frac{1}{\cos \theta }[/tex] , so , [tex]\sec \theta =\frac{1}{\frac{9}{10} }=\frac{10}{9}[/tex]