The mass of water needed to absorb 456 J is 1.44 g
We'll begin by calculating the change in the temperature of the water.
Initial temperature of water (T₁) = 22.7 °C
Final temperature (T₂) = 98.3 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 98.3 – 22.7
ΔT = 75.6 °C
- Finally, we shall determine the mass of the water
Heat absorbed (Q) = 456 J
Change in temperature (ΔT) = 75.6 °C
Specific heat capacity of water (C) = 4.184 J/gºC
Mass of water (M) =?
Q = MCΔT
456 = M × 4.184 × 75.6
456 = M × 316.3104
Divide both side by 316.3104
M = 456 / 316.3104
M = 1.44 g
Therefore, the mass of the water is 1.44 g
Learn more: https://brainly.com/question/15563205
