You are driving your car around a roundabout when you get a flat tire and you decelerate at a constant rate to a stop. The diameter of the roundabout is 100m. It takes you 20 sec to come to a complete stop. While slowing down, you continue to drive in a circle and you stop halfway around the loop. What must your speed have been before the pop?

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06-12-2021
Physics

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You are driving your car around a roundabout when you get a flat tire and you decelerate at a constant rate to a stop. The diameter of the roundabout is 100m. It takes you 20 sec to come to a complete stop. While slowing down, you continue to drive in a circle and you stop halfway around the loop. What must your speed have been before the pop?

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martingodoy1406 martingodoy1406 · Answer 1 · 2021-12-06T04:31:46+01:00

martingodoy1406 martingodoy1406

06-12-2021

Answer:

2.5 meters per second

Explanation:

stops half way which is 50m and if its at a constant speed of 2.5 meters multiply that by the seconds and you get 50m

Answer Link

alokdubeyvidyaatech alokdubeyvidyaatech · Answer 2 · 2022-03-08T14:45:25+01:00

The speed depends on the distance and time. The speed before the pop is 2.5 m/s.

What is the speed?

The speed of an object is defined as the total distance traveled by the object within a given time interval.

Given that the diameter of the roundabout is 100m. It takes you 20 sec to come to a complete stop.

While slowing down, you continue to drive in a circle and you stop halfway around the loop. It means that the half distance is 50 m. The speed is calculated as given below.

[tex]s = \dfrac {D}{t}[/tex]

[tex]s = \dfrac {50}{20}[/tex]

[tex]s = 2.5 \;\rm m/s[/tex]

Hence we can conclude that the speed before the pop is 2.5 m/s.

To know more about the speed, follow the link given below.

https://brainly.com/question/12759408.