Respuesta :
Data:
x (batter number) = ?
Solving:
[tex]x + 6 \frac{3}{4} = 12[/tex]
[tex]x = 12 - 6 \frac{3}{4} [/tex]
[tex]x = 12 - \frac{4*6+3}{4} [/tex]
[tex]x = 12 - \frac{24+3}{4} [/tex]
[tex]x = 12 - \frac{27}{4} [/tex]
least common multiple (LCM) = 4, Will be the denominator:
[tex]x = 12 - \frac{27}{4} [/tex]
[tex] \frac{4\div1*x}{4} = \frac{4\div1*12}{4} - \frac{4\div4*27}{4} [/tex]
[tex]\frac{4x}{\diagup\!\!\!\!4} = \frac{48}{\diagup\!\!\!\!4} - \frac{27}{\diagup\!\!\!\!4}[/tex]
[tex]4x = 48 - 27[/tex]
[tex]4x = 21[/tex]
[tex]x = \frac{21}{4} [/tex]
Transform into mixed fraction
........................21 |_4_← denominator
....numerator→(1)....5 ← whole number
Therefore, We have:
[tex]x = \frac{21}{4} =\boxed{ 5 \frac{1}{4} }[/tex]
Answer:
Jamal need [tex] 5\frac{1}{4} [/tex] cups of batter
x (batter number) = ?
Solving:
[tex]x + 6 \frac{3}{4} = 12[/tex]
[tex]x = 12 - 6 \frac{3}{4} [/tex]
[tex]x = 12 - \frac{4*6+3}{4} [/tex]
[tex]x = 12 - \frac{24+3}{4} [/tex]
[tex]x = 12 - \frac{27}{4} [/tex]
least common multiple (LCM) = 4, Will be the denominator:
[tex]x = 12 - \frac{27}{4} [/tex]
[tex] \frac{4\div1*x}{4} = \frac{4\div1*12}{4} - \frac{4\div4*27}{4} [/tex]
[tex]\frac{4x}{\diagup\!\!\!\!4} = \frac{48}{\diagup\!\!\!\!4} - \frac{27}{\diagup\!\!\!\!4}[/tex]
[tex]4x = 48 - 27[/tex]
[tex]4x = 21[/tex]
[tex]x = \frac{21}{4} [/tex]
Transform into mixed fraction
........................21 |_4_← denominator
....numerator→(1)....5 ← whole number
Therefore, We have:
[tex]x = \frac{21}{4} =\boxed{ 5 \frac{1}{4} }[/tex]
Answer:
Jamal need [tex] 5\frac{1}{4} [/tex] cups of batter