The slope of the line that is perpendicular to line AB is: 1/2.
Recall:
- If line A has a slope of "-a" and it is perpendicular to line B, therefore, the slope of line B will be the negative reciprocal of line A which is 1/a.
- Slope (m) = change in y / change in x = [tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Given:
A(-1,10)
B(5,-2)
Slope of AB:
[tex]m = \frac{-2 - 10}{5 -(-1)} = \frac{-12}{6} \\\\\mathbf{m = -2}[/tex]
The slope of the line that is perpendicular to line AB will be the negative reciprocal of the slope of AB.
Therefore, the slope of the line perpendicular to AB is: 1/2.
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