15 POINTS AND BRANLIEST
Find the area of the figures below

[tex]Area = \frac{(6 + 10) \times 7}{2} \\ [/tex]
[tex]Area = \frac{16 \times 7}{2} \\ [/tex]
[tex]Area = \frac{2 \times 8 \times 7}{2} \\ [/tex]
[tex]Area = 8 \times 7[/tex]
[tex]Area = 56 \: \: {in}^{2} [/tex]
Answer:
Area: [tex]56in^2[/tex]
Step-by-step explanation:
The formula for the area of a trapezoid is:
[tex]A = \frac{a+b}{2}h[/tex]
so replacing with the given values we get:
[tex]a = 6in\\h = 7in\\b = 10in[/tex]
[tex]A = \frac{6in+10in}{2}7in = 56in^2[/tex]
So our final answer is [tex]56in^2[/tex]