An atom's electron configuration ends with 3p4. If another atom has seven more electrons, what would be the continuation of the electron configuration?

The continuation of the electron configuration would be [tex]3p^6, 4S^2, 3d^3[/tex].
The initial p orbital is partially filled. Hence, it has to be completely filled first in order to obey the orbital filling rule. Lower energy orbitals are first filled before higher energy orbitals.
After filling the p orbital with 2 electrons from the remaining 7 electrons, higher energy orbital 4s and 3d can then be filled.
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