Answer:
Midpoint : (4,3)
Step-by-step explanation:
midpoint = [tex](\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex]
Where the x and y values are derived from the given points.
We are given points H and K which are at (2,2) and (6,4)
We have (x1,y1) = (2,2) so x1 = 2 and y2 = 2
As well as (x2,y2) = (6,4) so x2 = 6 and y2 = 4
To find the midpoint we simply plug in the values of x and y into the formula
Recall the formula [tex](\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex]
x1 = 2 , x2 = 6 , y1 = 2 and y2 = 4
plug in these values into the formula
[tex](\frac{2+6}{2} ,\frac{2+4}{2} )[/tex]
add top values: 2 + 6 = 8 and 2 + 4 = 6
[tex](\frac{8}{2} ,\frac{6}{2} )[/tex]
simplify fractions : 8/2 = 4 and 6/2 = 3
The midpoint is at [tex](4,3)[/tex]
