The volume of the sodium hydroxide solution needed for the reaction is 0.3 L
We'll begin by writing the balanced equation for the reaction.
H₂X + 2NaOH → 2H₂O + Na₂X
From the balanced equation above, the following data were obtained:
- The mole ratio of the acid, H₂X (nA) = 1
- The mole ratio of base, NaOH (nB) = 2
From the question given above, the following data were obtained:
- Molarity of base, NaOH (Mb) = 0.2 M.
- Volume of acid, H₂X (Va) = 0.3 L.
- Molarity of acid, H₂X (Ma) = 0.1 M.
- Volume of base, NaOH (Vb) =?
MaVa / MbVb = nA / nB
(0.1 × 0.3) / (0.2 × Vb) = 1/2
0.03 / (0.2 × Vb) = 1/2
Cross multiply
0.03 × 2 = 0.2 × Vb
0.06 = 0.2 × Vb
Divide both side by 0.2
Vb = 0.06 / 0.2
Vb = 0.3 L
Therefore, the volume of NaOH needed for the reaction is 0.3 L
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