What is the standard form of the parabola whose vertex form is y= 2(x+4)^2+5
A. y = 2x2 +16x - 37
B. y=-2x² + 4x - 25
C. y = 2x° +16x +37
D. y = 2x² + 4x - 25

Respuesta :

[tex]y = 2(x+4)^2+5\implies y = 2(x+4)(x+4)+5 \\\\\\ y = 2(\stackrel{\mathbb{USING~FOIL}}{x^2+8x+16})+5\implies y= 2x^2+16x+32+5 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y = 2x^2+16x+37~\hfill[/tex]