If the pair of points (5, 6) and (10, y) lie on a line with slope 4/5, then the value of y is 10
The slope m of the line passing through the points [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] is calculated as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
For the line passing through points (5, 6) and (10, y)
[tex]x_1=5, y_1=6, x_2=10, y_2=y[/tex]
The slope, m = 4/5
Substitute these value into the slope formula and solve for y
[tex]m=\frac{y_2-y_1}{x_2-x_1} \\\\\frac{4}{5}=\frac{y-6}{10-5} \\\\\frac{4}{5}=\frac{y-6}{5}[/tex]
Cross multiply:
4(5) = 5(y-6)
4 = y - 6
Collect like terms
y = 4 + 6
y = 10
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