When [tex]^1^8F[/tex] undergoes positron emission, the product nucleus is, [tex]^1^8O[/tex].
In positron emission, also called positive beta decay (β+ decay), a proton in the parent nucleus decays into a neutron that remains in the daughter nucleus, and the nucleus emits a neutrino and a positron, which is a positive particle like an ordinary electron in mass but of opposite charge.
When a proton is converted into a neutron then the positron emission takes place as follows.
[tex]^1_1p\;\rightarrow\;^1_0n\;+\;^0_+1e[/tex]
A positron is represented by the symbol. Therefore, when a positron emission occurs then the resultant nuclei atomic number decreases by a unit mass.
The general equation representing positron emission is as follows.
[tex]^M_ZA\;\rightarrow\;^M_Z_-_1 B\;+\;^0_+1e[/tex]
Hence, fluorine-18 decays by positron emission as follows.
[tex]^1^8_9F\;\rightarrow\;^1^8_8n\;+\;^0_+1e[/tex]
Therefore, when [tex]^1^8F[/tex] undergoes positron emission, the product nucleus is, [tex]^1^8O[/tex].
Learn more about positron emission here:
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