Respuesta :

Answer: Choice C

Work Shown:

[tex]\frac{1+\sqrt{-32}}{4}\\\\\frac{1+\sqrt{-1*16*2}}{4}\\\\\frac{1+\sqrt{-1}*\sqrt{16}*\sqrt{2}}{4}\\\\\frac{1+i*4*\sqrt{2}}{4}\\\\\frac{1+4i*\sqrt{2}}{4}\\\\\frac{1}{4}+\frac{4i*\sqrt{2}}{4}\\\\\boldsymbol{\frac{1}{4}+i\sqrt{2}}\\\\[/tex]

This matches with choice C. The imaginary 'i' term is not under the square root.