Using the binomial distribution, it is found that the mean of X is of 12, with a standard deviation of 3.36.
For each chip, there are only two possible outcomes, either it is defective, or it is not. The probability of a chip being defective is independent of any other chip, hence, the binomial distribution is used to solve this question.
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
The mean of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
In this problem:
- Six percent of computer chips produced by Cheapo Chips are defective, hence [tex]p = 0.06[/tex].
- Each month a random sample of 200 chips manufactured that month are taken, hence [tex]n = 200[/tex]
Then:
[tex]E(X) = np = 200(0.06) = 12[/tex]
[tex]\sqrt{V(X)} = \sqrt{np(1 - p)} = \sqrt{200(0.06)(0.94)} = 3.36[/tex]
The mean of X is of 12, with a standard deviation of 3.36.
A similar problem is given at https://brainly.com/question/12473640
