As part of a large poster, a graphic designer dilates a rectangular image so its length in the poster is 46 inches and its width is 21 inches. The original image has dimensions that are 3/8 of the dimensions of the image in the poster. What is the width of the original image?
(A) 2 inches (c) 101 inches
(B) 7 7/8 inches (D) 17 1/4 inches

As part of a large poster a graphic designer dilates a rectangular image so its length in the poster is 46 inches and its width is 21 inches The original image class=

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Answer:

B

Step-by-step explanation:

21 inches to 7 inches

The width of the original image is B)  [tex]7\frac{7}{8}[/tex] inches.

Given that: The width of the large poster is 21 inches.

Given that: The original image has dimensions that are 3/8 of the dimensions of the image in the poster.

So the width of the original image is = [tex]\frac{3}{8}\cdot21=\frac{63}{8}=7\frac{7}{8}[/tex]

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