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A child on a spinning ride at a playground has a centripetal acceleration of 0. 80 m/s2. The child completes a full circle every 4. 2 s. How far from the center of the ride is the child? 0. 068 m 0. 085 m 0. 27 m 0. 36 m.

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onyebuchinnaji

The distance of the child from the center of the ride is 0.28 m.

The given parameters;

  • Centripetal acceleration of the child, a = 0.8 m/s²
  • Number of revolution, = 1 rev per 4.2 s

The angular speed of the child is calculated as follows;

[tex]\omega = \frac{1 \ rev}{4.2 \ s} \times \frac{2 \pi \ rad}{1 \ rev} \\\\\omega = 1.5 \ rad/s[/tex]

The radius of the circle is calculated as follows;

[tex]a_c = \omega ^2 r\\\\r = \frac{a_c }{\omega ^2} \\\\r = \frac{0.8}{1.5^2} \\\\r = 0.28 \ m[/tex]

Thus, the distance of the child from the center of the ride is 0.28 m.

Learn more about angular speed here: https://brainly.com/question/6860269

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