Answer:
Option A
Step-by-step explanation:
Given equation is:
[tex]x^2+1=2x-3[/tex]
Setting it up as a quadratic equation.
[tex]x^2+1-2x+3=0\\\\x^2-2x+4=0[/tex]
Comparing it with quadratic equation [tex]ax^2+bx+c=0[/tex], we get:
a = 1 , b = -2 , c = 4
Putting the values in quadratic equation:
[tex]\displaystyle x = \frac{-b +-\sqrt{b^2-4ac} }{2a} \\\\x = \frac{-(-2)+-\sqrt{(-2)^2-4(1)(4)} }{2(1)}[/tex]
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807
