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Jake has two dogs, Euclid and Pythagoras. Euclid is a smaller dog and Pythagoras is larger. Jake found that
Pythagoras lost 13 pounds from January to June. If Pythagoras gains 1.2 times Euclid's weight, Pythagoras's
weight would still be á pound less than he did in January. What is Euclid's weight?
4
(a) Write an equation that represents the scenario. Begin by defining your variable.
(b) Solve the equation. Show your work.
(c) What is Euclid's weight?
(d) Jake adopts a third dog, Riemann. Riemann weighs exactly twice what Euclid weighs. The combined
weight of the three dogs is 603 pounds. What is Riemann's weight, and what is Pythagoras's
2
weight? Show your work.

Respuesta :

facundo3141592

We want to answer different things about the weight of the dogs, with simple algebra we will find that the answers are:

  • a) P - 13lb + 1.2*E = P - 1lb
  • b) E =  10lb
  • c) Euclid's weight is 10 pounds.
  • d) Pythagora's weight is 33 pounds and Riemann's weight is 20 pounds.

We start by defining the two variables we will be using:

  • E = Euclid's weight
  • P = Pythagoras's weight

First, Pythagoras loses 13 lb, then his new weight is:

P' = P - 13lb

We know that if he wins 1.2 Euclid's weight, he will still have a pound less than before.

A) using the above information we can rewrite:

P - 13lb + 1.2*E = P - 1lb

This is the equation we need to solve.

b) So we want to solve this for E, then we move all the other terms to the right side:

1.2E = P - 1lb - P + 13lb

1.2E = 12lb

E = (12lb)/1.2 = 10lb

c) The solution of the above equation tells us that the weight of the dog is 10lb.

d) Let's define R as the weight of the third dog.

We know that:

R = 2*E = 2*10lb = 20lb

We also know that the combined weight of the 3 dogs is 63 lb, then we have:

E + R + P = 63lb

10lb + 20lb + P = 63lb

P = 63lb - 10lb -20lb = 33lb

If you want to learn more about algebra, you can read:

https://brainly.com/question/20607627

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