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After Gwen, Tristan, and Keith finish exercising, they go to the fair. At the fair, they each pay the entry fee and also buy tickets they can use for food or rides. Gwen pays the entry fee and buys 10 tickets. It costs her a total of $30. Tristan pays the entry fee and buys 15 tickets. It costs him a total of $40. Keith pays the entry fee and buys 10 tickets. It costs him a total of $30. In this task, you will create a system of equations and find the cost of each ticket. Let x represent the entry fee and y represent the cost of each ticket in dollars.

After Gwen Tristan and Keith finish exercising they go to the fair At the fair they each pay the entry fee and also buy tickets they can use for food or rides G class=
After Gwen Tristan and Keith finish exercising they go to the fair At the fair they each pay the entry fee and also buy tickets they can use for food or rides G class=
After Gwen Tristan and Keith finish exercising they go to the fair At the fair they each pay the entry fee and also buy tickets they can use for food or rides G class=
After Gwen Tristan and Keith finish exercising they go to the fair At the fair they each pay the entry fee and also buy tickets they can use for food or rides G class=
After Gwen Tristan and Keith finish exercising they go to the fair At the fair they each pay the entry fee and also buy tickets they can use for food or rides G class=

Respuesta :

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Answer:

Part A:

Gwen equation

x + 10y = 30

Part C:

Keith equation:

x + 10y = 30

Part B:

Tristan equation:

x + 15y = 40

Part D:

You would use Keith's and Tristan's equation, because Gwen and Keith have the same exact equation so you can just use Keith's equation.

Part E:

Multiply the second equation by -1, then add the equations together.

(x+10y=30)

-1(x+15y=40)

Becomes:

x + 10y = 30

-x - 15y = - 40

Add these equations to eliminate x:

-5y = -10

-5y/5 = -10/5

so y = 2

Now lets find x, so lets plug it in x + 10y = 30.

x + 10(2) = 30

x + 20 = 30 ( do 30-20)

x = 10

We used elimination to solve this problem.

The entree fee is $10 and each ticket costs $2.

Part F:

For this part search graph tool and go on the app, then put Keith's and Tristan's equation in Graph Tool. Once you do that just screenshot it and paste it to Part F, then your answer should be Yes, you get the same solution when it is solved algrebraically.

Step-by-step explanation:

I really hope this helps you!!!! :D Mark brainliest if it does!!!!

Notsheest

Answer: Part A:

Gwen equation

x + 10y = 30

Part C:

Keith equation:

x + 10y = 30

Part B:

Tristan equation:

x + 15y = 40

Part D:

You would use Keith's and Tristan's equation, because Gwen and Keith have the same exact equation so you can just use Keith's equation.

Part E:

Multiply the second equation by -1, then add the equations together.

(x+10y=30)

-1(x+15y=40)

Becomes:

x + 10y = 30

-x - 15y = - 40

Add these equations to eliminate x:

-5y = -10

-5y/5 = -10/5

so y = 2

Now lets find x, so lets plug it in x + 10y = 30.

x + 10(2) = 30

x + 20 = 30 ( do 30-20)

x = 10

We used elimination to solve this problem.

The entree fee is $10 and each ticket costs $2.

Part F:

For this part search graph tool and go on the app, then put Keith's and Tristan's equation in Graph Tool. Once you do that just screenshot it and paste it to Part F, then your answer should be Yes, you get the same solution when it is solved algrebraically.

Step-by-step explanation:

I really hope this helps you!!!! :D Mark brainliest if it does!!!!

Step-by-step explanation:

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