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Consider the reaction below. Upper C upper C l subscript 5 (g) double-headed arrow upper P upper C l subscript 3 (g) plus upper C l subscript 2 (g). At 500 K, the reaction is at equilibrium with the following concentrations. [PCI5]= 0. 0095 M [PCI3] = 0. 020 [CI2] = 0. 020 M What is the equilibrium constant for the given reaction? 0. 042 0. 42 2. 4 24.

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The equilibrium constant of the reaction is 0.042.

The reaction equation is given as;

PCl5(g) ⇄ PCl3(g) + Cl2 (g)

Recall that this equation shows the decomposition of phosphorus pentachloride.

We have the following equilibrium concentrations;

[PCI5]= 0.0095 M

[PCI3] = 0.020

[CI2] = 0.020 M

The equilibrium constant, K is obtained from;

K =  [PCI3]  [CI2]/[PCI5]

K = [0.020]^2/[0.0095]

K = 0.042

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