Given that ΔQSR and ΔTSU are similar triangles, therefore, the length of SU is: 20.
Recall:
Thus, given the figure attached below, ΔQSR and ΔTSU are similar to each other.
SR/SU = QR/TU
SR = RU + SU = 12 + SU
SU = ?
QR = 40
TU = 25
Plug in the values
[tex]\frac{12 + SU}{SU} = \frac{40}{25}[/tex]
[tex](12 + SU)25 = 40(SU)\\\\300 + 25SU = 40SU\\\\300 = 40SU - 25SU\\\\300 = 15SU\\\\\mathbf{SU = 20}[/tex]
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